MCQ
Differential equation whose solution is $y = cx + c - {c^3}$, is
  • A
    $\frac{{dy}}{{dx}} = c$
  • $y = x\frac{{dy}}{{dx}} + \frac{{dy}}{{dx}} - {\left( {\frac{{dy}}{{dx}}} \right)^3}$
  • C
    $\frac{{dy}}{{dx}} = c - 3{c^2}$
  • D
    None of these

Answer

Correct option: B.
$y = x\frac{{dy}}{{dx}} + \frac{{dy}}{{dx}} - {\left( {\frac{{dy}}{{dx}}} \right)^3}$
b
(b) Differentiating, we have $\frac{{dy}}{{dx}} = c$

Hence differential equation is, $y = x\frac{{dy}}{{dx}} + \frac{{dy}}{{dx}} - {\left( {\frac{{dy}}{{dx}}} \right)^3}$.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

Let $a = 2i + j + k,\,\,b = i + 2j - k$and $a$  unit vector $ c$ be coplanar. If $ c $is perpendicular to $ a$ , then $ c $=
A point out of following points lie in plane represented by
The mapping $f : N \rightarrow N$ is given by $f(n) = 1 + n^2, n \in N$ when $N$ is the set of natural numbers is:
Which of the following is(are) $NOT$ the square of a $3 \times 3$ matrix with real entries ?

$[A]$ $\left[\begin{array}{ccc}1 & 0 & 0 \\ 0 & 1 & 0 \\ 0 & 0 & -1\end{array}\right]$

$[B]$ $\left[\begin{array}{ccc}-1 & 0 & 0 \\ 0 & -1 & 0 \\ 0 & 0 & -1\end{array}\right]$

$[C]$ $\left[\begin{array}{lll}1 & 0 & 0 \\ 0 & 1 & 0 \\ 0 & 0 & 1\end{array}\right]$

$[D]$ $\left[\begin{array}{ccc}1 & 0 & 0 \\ 0 & -1 & 0 \\ 0 & 0 & -1\end{array}\right]$

If $A$ and $B$ are events such that $P(A)>0$ and $P(B) \neq 1$, then $P\left(A^{\prime} \mid B^{\prime}\right)$ equals
If $\theta$ is the angle between two vectors $\vec{a}$ and $\vec{b}$, then $\vec{a} \cdot \vec{b} \geq 0$ only when
If linear functions $f(x)$ and $g(x)$ satisfy $\int {\left[ {\left( {1 - 2x} \right)\cos x+\left( {3 + 2x} \right)\sin x} \right]} dx$ = $f\left( x \right)\sin x + g\left( x \right)\cos x + C$ (where $C$ is constant of integration), then
The value of $\int_{\,a}^{\,b} {\frac{x}{{|x|}}dx,\,\,a < b < 0} $ is
If $A = \left[ {\begin{array}{*{20}{c}}0&2&0\\0&0&3\\{ - 2}&2&0\end{array}} \right]$and $B = \left[ {\begin{array}{*{20}{c}}1&2&3\\3&4&5\\5&{ - 4}&0\end{array}} \right]$, then the element of $3^{rd}$ row and third column in $AB$ will be
If the shortest distance between the lines $\frac{\mathrm{x}-\lambda}{2}=\frac{\mathrm{y}-4}{3}=\frac{\mathrm{z}-3}{4}$ and $\frac{x-2}{4}=\frac{y-4}{6}=\frac{z-7}{8}$ is $\frac{13}{\sqrt{29}}$, then a value of $\lambda$ is :