Question
Differentiate between lanthanoids and actinoids.

Answer

Lanthanoids Actinoids
Electronic configuration $[Xe] 4f^{1-14} 5d^{0-1}, 6s^2$ Electronic configuration $[Rn] 5f^{1-14} 6d^{0-1}, 7s^2$
The differentiating electron enters the $4f$ subshell. The differentiating electron enters the 5f subshell.
Except for Promethium all other elements occur in nature. Except for Uranium and Thorium, all others are synthesized in the laboratory.
The binding energy of $4f$ electrons is higher. $5f$-orbitals have lower binding energy.
Only Promethium is radioactive. All elements are radioactive.
Besides $3$ + oxidation state they show $2$ + and $4$ + oxidation states. Besides $3$ + oxidation state they show $2 + , 4 + , 5 + , 6 + , 7$ + oxidation states.
They have a less tendency to form complexes. They have greater tendency to form complexes.
Many lanthanoid ions are colourless. Their colour is not as deep and sharp as actinoids. Actinoids are coloured ions. Their colour is deep, e.g. $U^{3+}$ is red and $U^{4+}$​​​​​​​ is green.
Lanthanoids cannot form oxo-cations. Actinoids form oxo-cations such as $– UO_2^+, PuO_2^+, UO_2^{2+}, PuO_2^{2+}.$
Lanthanoid hydroxides are less basic. Actinoid hydroxides are more basic.
Lanthanoid contraction is relatively less. Actinoid contraction from element to element is comparatively more.
Mutual shielding of $4f$ electrons is more. Mutual shielding effect of $5f$ electrons is less.

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