Question
Differentiate $e^{sin^{-1}x}$ w.r.t. x.

Answer

Let $y = e^{sin^{-1}x}$
Now, by using the chain rule, we get,
$\frac{d y}{d x}=\frac{d}{d x}\left(e^{\sin ^{-1} x}\right)$
$\Rightarrow \frac{d y}{d x}=e^{\sin ^{-1} x} \cdot \frac{d}{d x}\left(\sin ^{-1} x\right)$
= $e^{\sin ^{-1} x} \cdot \frac{1}{\sqrt{1-x^{2}}}$
= $\frac{e^{\sin ^{-1} x}}{\sqrt{1-x^{2}}}$
Thus $\frac{d y}{d x}=\frac{e^{\sin ^{-1} x}}{\sqrt{1-x^{2}}}$

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