Question
Differentiate sin2 x w.r.t. ecos x.

Answer

Let u (x) = sin2 x and v (x) = ecos x . We want to find $\frac{d u}{d v}=\frac{d u / d x}{d v / d x}$.
Clearly $\frac{d u}{d x} $ = 2 sin x cos x
and      $\frac{d v}{d x}$ = ecos x (– sin x) = – (sin x) ecos x
$\therefore$         $\frac{d u}{d v}=\frac{2 \sin x \cos x}{-\sin x e^{\cos x}}=-\frac{2 \cos x}{e^{\cos x}}$

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