Question
Differentiate the following function with respect to $(\text{x})$:
$(2\text{x}^2+1)(3\text{x}+2)$
$(2\text{x}^2+1)(3\text{x}+2)$
$\frac{\text{d}}{\text{dx}}(2\text{x}^2+1)(3\text{x}+2)$
$=(3\text{x}+2)\frac{\text{d}}{\text{dx}}(2\text{x}^2+1)+(\text{2x}^2+1)\frac{\text{d}}{\text{dx}}(3\text{x}+2)$ [Using product rule]
$=(3\text{x}+2)(4\text{x}+0)+(\text{2x}^2+1)(3+0)$
$=(12\text{x}^2+\text{8x}+\text{6x}^2+3)$
$=18\text{x}^2+\text{8x}+3$
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.