Question
Differentiate the following function with respect to $(\text{x})$:
$3^\text{x}+\text{x}^3+3^3$
$3^\text{x}+\text{x}^3+3^3$
$\frac{\text{d}}{\text{dx}}(3^\text{x}+\text{x}^3+3^3)$
$=\frac{\text{d}}{\text{dx}}(3^\text{x})+\frac{\text{d}}{\text{dx}}(\text{x}^3)+\frac{\text{d}}{\text{dx}}(3^3)$
$=3^\text{x}\log3+3\text{x}^2+0\ \Bigg[\because\frac{\text{d}}{\text{dx}}(\text{a}^\text{x})=\text{a}^\text{x}\log\text{a}\Bigg]$
$=3^\text{x}\log3+3\text{x}^2$
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