Question
Differentiate the following function with respect to $(\text{x})$:
$\frac{2\text{x}^2+\text{3x}+4}{\text{x}}$
$\frac{2\text{x}^2+\text{3x}+4}{\text{x}}$
$\frac{\text{d}}{\text{dx}}\Big(\frac{2\text{x}^2+\text{3x}+4}{\text{x}}\Big)$
$=\frac{\text{d}}{\text{dx}}\Big(\frac{\text{2x}^2}{\text{x}}+\frac{\text{3x}}{\text{x}}+\frac{4}{\text{x}}\Big)$
$=\frac{\text{d}}{\text{dx}}(\text{2x}+3+4\text{x}^{-1})$
$=2-\frac{4}{\text{x}^2}$
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