CBSE BoardEnglish MediumSTD 11 ScienceMathsDerivatives2 Marks
Question
Differentiate the following function with respect to x:
$\sin\text{x}\cos\text{x}$
✓
Answer
Let $\text{u}=\sin\text{x};\text{v}=\cos\text{x}$Then, $\text{u}'=\cos\text{x};\text{v}'=-\sin\text{x}$
Using the product rule:
$\frac{\text{d}}{\text{dx}}(\text{uv})=\text{uv}'+\text{vu}'$
$\frac{\text{d}}{\text{dx}}(\sin\text{x}\cos\text{x})=\sin\text{x}(-\sin\text{x})+\cos\text{x}.\cos\text{x}$
$=-\sin^2\text{x}+\cos^2\text{x}$
$=\cos2\text{x}$
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.