Question
Differentiate the following function with respect to $\text{x}$:
$\text{x}^3\text{e}^\text{x}$
$\text{x}^3\text{e}^\text{x}$
Then,
$\text{u}'=3\text{x}^2;\text{v}'=\text{e}^\text{x}$Using the product rule:
$\frac{\text{d}}{\text{dx}}(\text{uv})=\text{uv}'+\text{vu}'$
$\frac{\text{d}}{\text{dx}}(\text{x}^3\text{e}^\text{x})=\text{x}^3\text{e}^\text{x}+\text{e}^\text{x}(3\text{x}^2)$
$=\text{x}^2\text{e}^\text{x}(\text{x}+3)$
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
| x | 1 | 2 | 3 | 4 | 5 | 6 | 7 |
| y | f (1) = ... | f (2) = ... | f (3) = ... | f (4) = ... | f (5) = ... | f (6) = ... | f (7) = ... |