Question
Differentiate the following function with respect to x:

$\text{x}^5(3-\text{6x}^{-9})$

Answer

Let $\text{u}=\text{x}^5;\text{v}=(3-\text{6x}^{-9})$

Then, $\text{u}'=\text{5x}^4;\text{v}'=\text{54x}^{-10}$

Using the product rule:

$\frac{\text{d}}{\text{dx}}(\text{uv})=\text{uv}'+\text{vu}'$

$\frac{\text{d}}{\text{dx}}[\text{x}^5(3-\text{6x}^9)]=\text{x}^5(\text{54x}^{-10})+\text{5x}^4(3-\text{6x}^9)$

$=\text{54x}^{-5}+\text{15x}^4-\text{30x}^{-5}$

$=\text{15x}^4+\text{24x}^{-5}$

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