Question
Differentiate the following functions with respect to x:
$\frac{1}{\text{ax}^2+\text{bx}+\text{c}}$
$\frac{1}{\text{ax}^2+\text{bx}+\text{c}}$
$=\frac{(\text{ax}^2+\text{bx}+\text{c})\frac{\text{d}}{\text{dx}}(1)-1\frac{\text{d}}{\text{dx}}(\text{ax}^2+\text{bx}+\text{c})}{(\text{ax}^2+\text{bx}+\text{c})^2}$
$=\frac{-(\text{2ax}+\text{b})}{(\text{ax}^2+\text{bx}+\text{c})^2}$
$\therefore\frac{\text{d}}{\text{dx}}\frac{1}{\text{ax}^2+\text{bx}+\text{c}}=\frac{-(\text{2ax}+\text{b})}{(\text{ax}^2+\text{bx}+\text{c})^2}$
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