Question
Differentiate the following functions with respect to x:

$\frac{\text{x}}{1+\tan\text{x}}$

Answer

We have,

$\frac{\text{d}}{\text{dx}}\Big(\frac{\text{x}}{1+\tan\text{x}}\Big)$

Using quotient rule, we get

$\frac{(1+\tan\text{x})\frac{\text{d}}{\text{dx}}(\text{x})-(\text{x})\frac{\text{d}}{\text{dx}}(1+\tan\text{x})}{(1+\tan\text{x})^2}$

$=\frac{(1+\tan\text{x})-\text{x}\sec^2\text{x}}{(1+\tan\text{x})^2}$

$=\frac{1+\tan\text{x}-\text{x}\sec^2\text{x}}{(1+\tan\text{x})^2}$

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