Gujarat BoardEnglish MediumSTD 12 ScienceMathsDifferentiation3 Marks
Question
Differentiate the following functions with respect to x: $\tan^{-1}(\text{e}^{\text{x}})$
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Answer
Consider $\text{y}=\tan^{-1}(\text{e}^{\text{x}})$ Differentiate with respect to x, $\frac{\text{dy}}{\text{dx}}=\frac{\text{d}}{\text{dx}}\big(\tan^{-1}\text{e}^{\text{x}}\big)$ $=\frac{1}{1+\big(\text{e}^{2\text{x}}\big)^2}=\frac{\text{d}}{\text{dx}}\big(\text{e}^\text{x}\big)$ [using chain rule] $=\frac{1}{1+\text{e}^{2\text{x}}}\times\text{e}^\text{x}$ $=\frac{\text{e}^\text{x}}{1+\text{e}^{2\text{x}}}$ Hence, the solution is, $\frac{\text{d}}{\text{dx}}\big(\tan^{-1}\text{e}^\text{x}\big)=\frac{\text{e}^\text{x}}{1+\text{e}^{2\text{x}}}$
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