Question
Differentiate the following w. r. t. x.$\sin ^{-1}\left(\frac{2 x}{1+x^2}\right)$
\begin{array}{ll}
\text { Let } y=\sin ^{-1}\left(\frac{2 x}{1+x^2}\right) \\
& \text { Put } x=\tan \theta \therefore \theta=\tan ^{-1} x \\
\therefore \quad & y=\sin ^{-1}\left(\frac{2 \tan \theta}{1+\tan ^2 \theta}\right) \\
& y=\sin ^{-1}(\sin 2 \theta)=2 \theta \\
\therefore \quad & y=2 \tan ^{-1} x
\end{array}
$
Differentiate $w . r . t . x$.
$
\begin{aligned}
\frac{d y}{d x} & =2 \frac{d}{d x}\left(\tan ^{-1} x\right) \\
\therefore \quad \frac{d y}{d x} & =\frac{2}{1+x^2}
\end{aligned}
$
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