Question
Differentiate the following w.r.t. x. : $\sqrt{x}\left(x^2+1\right)^2$

Answer

$
\text { Let } \begin{aligned}
\mathrm{y} & =\sqrt{x}\left(x^2+1\right)^2 \\
y & =x^{\frac{1}{2}}\left(x^4+2 x^2+1\right) \\
y & =x^{\frac{9}{2}}+2 x^{\frac{5}{2}}+x^{\frac{1}{2}}
\end{aligned}
$
Differentiating w.r.t. $x$, we get
$
\begin{aligned}
\frac{\mathrm{d} y}{\mathrm{~d} x} & =\frac{\mathrm{d}}{\mathrm{d} x}\left(x^{\frac{9}{2}}+2 x^{\frac{5}{2}}+x^{\frac{1}{2}}\right) \\
& =\frac{\mathrm{d}}{\mathrm{d} x} x^{\frac{9}{2}}+2 \frac{\mathrm{d}}{\mathrm{d} x} x^{\frac{5}{2}}+\frac{\mathrm{d}}{\mathrm{d} x} \sqrt{x} \\
& =\frac{9}{2} x^{\frac{9}{2}-1}+2 \times \frac{5}{2} x^{\frac{5}{2}-1}+\frac{1}{2 \sqrt{x}} \\
& =\frac{9}{2} x^{\frac{7}{2}}+5 x^{\frac{3}{2}}+\frac{1}{2 \sqrt{x}}
\end{aligned}
$

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