Question
Differentiate the following w.r.t.x: $\log(\log\text{x}),\text{x}>1$

Answer

$\text{Let y}=\ \log(\log\text{x})$
$\therefore\ \frac{\text{dy}}{\text{dx}} =\frac{{1}}{{\log\text{x}}}.\frac{\text{d}}{\text{dx}}(\log\text{x})=\frac{{1}}{{\log\text{x}}}.\frac{\text{1}}{\text{x}}=\frac{1}{\text{x}\log\text{x}}$

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