Question
Differentiate the following w.r.t.x:

$\sqrt{\text{e}^\sqrt{\text{x}}},\ \text{x}>0$

Answer

$\text{Let}\ \sqrt{\text{e}^\sqrt{\text{x}}}=(\sqrt{\text{e}^\sqrt{\text{x}}})^{\frac{1}{2}}$
$\therefore\ \frac{\text{dy}}{\text{dx}} =\frac{{1}}{{2}} (\sqrt{\text{e}^\sqrt{\text{x}}})^{\frac{1}{2}}.\frac{\text{d}}{\text{dx}}(\sqrt{\text{e}^\sqrt{\text{x}}})=\frac{1}{2\sqrt{\text{e}^\sqrt{\text{x}}}}.\sqrt{\text{e}^\sqrt{\text{x}}}\frac{\text{d}}{\text{dx}}(\sqrt{\text{x}})$
$=\frac{1}{2\sqrt{\text{e}^\sqrt{\text{x}}}}.\text{e}\sqrt{\text{x}}.\frac{\text{1}}{{2\sqrt{\text{x}}}}=\frac{1}{4}\frac{{\text{e}^\sqrt{\text{x}}}}{\sqrt{\text{x e}^\sqrt{\text{x}}}}$

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