Question
Differentiate the function $sin ^{-1}({x\sqrt x})\ ,{0 \leq x \leq 1}$ w.r.t. to x.
$\therefore \frac{{dy}}{{dx}} = \frac{1}{{\sqrt {1 - \left( {{x^{\frac{3}{2}}}} \right)^2} }}\frac{d}{{dx}}{x^{\frac{3}{2}}}$
$= \frac{1}{{\sqrt {1 - {x^3}} }}.\frac{3}{2}{x^{\frac{1}{2}}}$
$= \frac{{3\sqrt x }}{{2\sqrt {1 - {x^3}} }}$
$= \frac{3}{2}\sqrt {\frac{x}{{1 - {x^3}}}}$
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