Question
Differentiate the function with respect to x : $\sec \left( {\tan \sqrt x } \right)$
$\therefore \frac{{dy}}{{dx}} = \sec \left( {\tan \sqrt x } \right)\tan \left( {\tan \sqrt x } \right)\frac{d}{{dx}}\left( {\tan \sqrt x } \right)$
$= \sec \left( {\tan \sqrt x } \right)\tan \left( {\tan \sqrt x } \right){\sec ^2}\sqrt x \frac{d}{{dx}}\sqrt x $
$= \sec \left( {\tan \sqrt x } \right)\tan \left( {\tan \sqrt x } \right){\sec ^2}\sqrt {x.} \frac{1}{2}{x^{\frac{1}{2} - 1}}$
$= \sec \left( {\tan \sqrt x } \right)\tan \left( {\tan \sqrt x } \right){\sec ^2}\sqrt x .\frac{1}{{2\sqrt x }}$
$= \frac{{\sec \left( {\tan \sqrt x } \right).\tan \left( {\tan \sqrt x } \right).{{\sec }^2}\sqrt x }}{{2\sqrt x }}$
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