Question
Differentiate the function with respect to x : $\sin \left( {{x^2} + 5} \right)$
$\therefore \frac{{dy}}{{dx}} = \cos \left( {{x^2} + 5} \right)\frac{d}{{dx}}\left( {{x^2} + 5} \right)$
$ = \cos \left( {{x^2} + 5} \right)\left( {2x + 0} \right)$
$= 2x\cos \left( {{x^2} + 5} \right)$
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| Xi | 0 | 1 | 2 |
| Pi | 3c3 | 4c - 10c2 | 5c - 1 |
Where c > 0
Find:
$\text{P}(1<\text{X}\leq2)$| $\text{X}$ | $0$ | $1$ | $2$ | $3$ |
| $\text{P}(\text{X})$ | $\text{k}$ | $\frac{\text{k}}{2}$ | $\frac{\text{k}}{4}$ | $\frac{\text{k}}{8}$ |
Determine the value of k.
| X: | 3 | 2 | 1 | 0 | -1 |
| P(X): | 0.3 | 0.2 | 0.4 | 0.1 | 0.05 |
| X: | 0.5 | 1 | 1.5 | 2 |
| P(X): | k | k2 | 2k2 | k |