Question
Differentiate the function with respect to x : $\sin \left( {{x^2} + 5} \right)$
✓
Answer
Let $y = \sin \left( {{x^2} + 5} \right)$
$\therefore \frac{{dy}}{{dx}} = \cos \left( {{x^2} + 5} \right)\frac{d}{{dx}}\left( {{x^2} + 5} \right)$
$ = \cos \left( {{x^2} + 5} \right)\left( {2x + 0} \right)$
$= 2x\cos \left( {{x^2} + 5} \right)$
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