Differentiate the function with respect to x: (3 x^2-x+1 )^4. - Vidyadip

Question

Differentiate the function with respect to $x:\left(3 x^2-x+1\right)^4$.

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Answer

To Find : $\frac{d}{d x}\left(3 x^2- x +1\right)^4$
Formula used: $\frac{d}{d x}\left(y^n\right)=n y^{ n -1} \times \frac{d y}{d x}$
Let $y=\left(3 x^2-x+1\right)^4$
So, by using the above formula, we have
$\frac{d}{d x}\left(3 x^2- x +1\right)^4=4\left(3 x ^2- x +1\right)^3 \times \frac{d}{d x}\left(3 x ^2- x +1\right)=4\left(3 x ^2- x +1\right)^3(6 x -1)$

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