CONTINUITY AND DIFFERENTIABILITY — Maths STD 12 Science — Question
Gujarat BoardEnglish MediumSTD 12 ScienceMathsCONTINUITY AND DIFFERENTIABILITY2 Marks
Question
Differentiate w.r.t. x the function in Exercise: $(3\text{x}^2-9\text{x}+5)^9$
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Answer
Let $\text{y}=(3\text{x}^2-9\text{x}+5)^9$ Using chain rule, we obtain $\frac{\text{dy}}{\text{dx}}=\frac{\text{d}}{\text{dx}}(3\text{x}^2-9\text{x}+5)^9$ $=9(3\text{x}^2-9\text{x}+5)^8.\frac{\text{d}}{\text{dx}}(3\text{x}^2-9\text{x}+5)$ $=9(3\text{x}^2-9\text{x}+5)^8.(6\text{x}-9)$ $=9(3\text{x}^2-9\text{x}+5)^8.3(2\text{x}-3)$ $=27(3\text{x}^2-9\text{x}+5)^8.3(2\text{x}-3)$
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