Question
Differentiate w.r.t. x the function in Exercise:
$\sin^3\text{x}+\cos^6\text{x}$
$\sin^3\text{x}+\cos^6\text{x}$
$\therefore\ \frac{\text{dy}}{\text{dx}}=\frac{\text{d}}{\text{dx}}(\sin^3\text{x})+\frac{\text{d}}{\text{dx}}(\cos^6\text{x})$
$=3\sin^2\text{x}.\frac{\text{d}}{\text{dx}}(\sin\text{x})+6\cos^5\text{x}.\frac{\text{d}}{\text{dx}}(\cos\text{x})$
$=3\sin^2\text{x}.\cos\text{x}+6\cos^5\text{x}.(-\sin\text{x})$
$=3\sin\text{x}\cos\text{x}(\sin\text{x}-2\cos^4\text{x})$Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
| Xi | 0 | 1 | 2 |
| Pi | 3c3 | 4c - 10c2 | 5c - 1 |
Where c > 0
Find: P(X < 2).
$\vec{\text{a}}=3\hat {\text{i}}-2\hat{\text{j}}-6\hat{\text{k}}$ and $\vec{\text{b}} =4\hat{\text{i}}-\hat{\text{j}}+8\hat{\text{k}}$