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Question Bank [2022] — Maths STD 12 Science — Question

Maharashtra BoardEnglish MediumSTD 12 ScienceMathsQuestion Bank [2022]1 Mark
Question
Differentiate $y =\sqrt{x^2+5}$ w.r. to $x$
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Answer

$ y =\sqrt{x^2+5}$
$\therefore \frac{ d y}{ d x}=\frac{ d }{ d x}\left(\sqrt{x^2+5}\right)$
$=\frac{1}{2 \sqrt{x^2+5}} \cdot \frac{ d }{ d x}\left(x^2+5\right)$
$=\frac{1}{2 \sqrt{x^2+5}} \cdot(2 x+0)$
$=\frac{x}{\sqrt{x^2+5}}$

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