Question
Diffrentiate the following w. r. t. x.
$\cot ^{-1}\left(\frac{a^2-6 x^2}{5 a x}\right)$
$\cot ^{-1}\left(\frac{a^2-6 x^2}{5 a x}\right)$
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is $\frac{1}{2}[\vec{a} \times \vec{b}+\vec{b} \times \vec{c}+\vec{c} \times \vec{a}]$
Question is modified.
Show that the area of a triangle $A B C$, the position vectors of whose vertices are $\bar{a}, \bar{b}$ and $\bar{c}$
is $\frac{1}{2}[\bar{a} \times \bar{b}+\bar{b} \times \bar{c}+\bar{c} \times \bar{a}]$.