Direction of the first secondary maximum in the Fraunhofer diffra… - Vidyadip

MCQ

Direction of the first secondary maximum in the Fraunhofer diffraction pattern at a single slit is given by (a is the width of the slit)

A
$a \sin \theta=\frac{\lambda}{2}$
B
$a \cos \theta=\frac{3 \lambda}{2}$
C
$a \sin \theta=\lambda$
✓
$a \sin \theta=\frac{3 \lambda}{2}$

✓

Answer

Correct option: D.

$a \sin \theta=\frac{3 \lambda}{2}$

$a \sin \theta=\frac{3 \lambda}{2}$

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