Question
दीर्घवृत्त $4{x^2} + {y^2} - 8x + 2y + 1 = 0$ की उत्केन्द्रता है
${(2x - 2)^2} + {(y + 1)^2} = - 1 + 4 + 1$
$\frac{{{{(x - 1)}^2}}}{1} + \frac{{{{(y + 1)}^2}}}{4} = 1$
$e = \sqrt {1 - \frac{1}{4}} $
$e = \frac{{\sqrt 3 }}{2}$.
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