Question
Discuss the relative stability in aqueous solutions of +2 oxidation state among the elements: Cr, Mn, Fe and Co. How would you justify this situation?
(At. Nos. Cr = 24, Mn = 25, Fe = 26, Co = 27)

Answer

On the basis of electrochemical series, the standard electrode potential shows the following order:
E°Mn2+/Mn < E°Cr2+/Cr < E°Fe2+/Fe < E°CO2+/CO
Therefore, Co2+ gets easily reduced to metallic cobalt while it is difficult to reduce Mn2+. Hence, Mn2+ will be the most stable and the increasing stability order will be
Co2+ < Fe2+ < Cr2+ < Mn2+

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