MCQ
Dissociation constant of a weak acid is $1 \times {10^{ - 4}}$. Equilibrium constant of its reaction with strong base is
- A$1 \times {10^{ - 4}}$
- ✓$1 \times {10^{10}}$
- C$1 \times {10^{ - 10}}$
- D$1 \times {10^{14}}$
✓
Answer
Correct option: B.
$1 \times {10^{10}}$
(b)${K_H} = \frac{{{K_a}}}{{{K_w}}} = \frac{{{{10}^{ - 4}}}}{{{{10}^{ - 14}}}} = \frac{1}{{{{10}^{ - 10}}}} = {10^{10}}$.
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