Distance of the point ( , , ) from y-axis is - Vidyadip

MCQ

Distance of the point $(\alpha, \beta, \gamma)$ from $y$-axis is

A
$\beta$
B
$|\beta|$
C
$|\beta|+|\gamma|$
✓
$\sqrt{\alpha^2+\gamma^2}$

✓

Answer

Correct option: D.

$\sqrt{\alpha^2+\gamma^2}$

(d) : Foot of perpendicular from $(\alpha, \beta, \gamma)$ on the $y$-axis is $(0, \beta, 0)$.
$\therefore \quad$ Distance of $(\alpha, \beta, \gamma)$ from $y$-axis $=$ distance of $(\alpha, \beta, \gamma)$ from $(0, \beta, 0)$
$
=\sqrt{(0-\alpha)^2+(\beta-\beta)^2+(0-\gamma)^2}=\sqrt{\alpha^2+\gamma^2}
$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

More "M.C.Q (1 Marks)" from Three Dimensional Geometry→Three Dimensional Geometry — all question types→Maths STD 12 Science question papers→Gujarat Board STD 12 Science question papers→Gujarat Board question paper generator→

Similar questions

If the points $(2k, k), (k, 2k)$ and $(k, k)$ with $k > 0$ enclose a triangle of area $18$ square unit then centroid of triangle is equal to

The area of the region bounded by the parabola $y=\sin ^2 x$, lines $x=\frac{\pi}{2}, x=\pi$ and $x$-axis is :

If $\tan^{-1}\text{x}-\tan^{-1}\text{y}=\tan^{-1}\text{A},$ then $A$ is equal to:

$\int_{\,0}^{\,2\pi } {|\sin x|\,dx = } $

$\int\frac{1}{\cos\text{x}+\sqrt{3}\sin\text{x}}\text{ dx}$ is equal to:

$\left| {\,\begin{array}{*{20}{c}}1&1&1\\1&{1 + x}&1\\1&1&{1 + y}\end{array}\,} \right| = $

Let $\Delta$ be the area of the region $\left\{( x , y ) \in R ^2: x ^2+ y ^2 \leq 21, y ^2 \leq 4 x , x \geq 1\right\}$. Then $\frac{1}{2}\left(\Delta-21 \sin ^{-1} \frac{2}{\sqrt{7}}\right)$ is equal to

The position vector of the point which divides the joining of points $2 \vec{a}-3 \vec{b}$ and $\vec{a}+\vec{b}$ in the ratio $3: 1$ is

If $l, m, n$ are the direction cosines of a line, then:

$D$ is a $3 \times 3$ diagonal matrix. Which of the following statements is not true?