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Three Dimensional Geometry — Maths STD 12 Science — Question

Gujarat BoardEnglish MediumSTD 12 ScienceMathsThree Dimensional Geometry1 Mark
MCQ
Distance of the point $(\alpha, \beta, \gamma)$ from $y$-axis is
  • A
    $\beta$
  • B
    $|\beta|$
  • C
    $|\beta|+|\gamma|$
  • ✓
    $\sqrt{\alpha^2+\gamma^2}$
✓

Answer

Correct option: D.
$\sqrt{\alpha^2+\gamma^2}$
(d) : Foot of perpendicular from $(\alpha, \beta, \gamma)$ on the $y$-axis is $(0, \beta, 0)$.
$\therefore \quad$ Distance of $(\alpha, \beta, \gamma)$ from $y$-axis $=$ distance of $(\alpha, \beta, \gamma)$ from $(0, \beta, 0)$
$
=\sqrt{(0-\alpha)^2+(\beta-\beta)^2+(0-\gamma)^2}=\sqrt{\alpha^2+\gamma^2}
$

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