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STD 11 - 3. trignometrical ratios,functions and identities — JEE STD 11 Science — Question

Gujarat BoardEnglish MediumSTD 11 ScienceJEESTD 11 - 3. trignometrical ratios,functions and identities4 Marks
Question
$\frac{1}{{\sin 10^\circ }} - \frac{{\sqrt 3 }}{{\cos 10^\circ }} =$
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Answer

d
(d) $\frac{1}{{\sin 10^\circ }} - \frac{{\sqrt 3 }}{{\cos 10^\circ }}$

$ = \frac{{2\left( {\frac{{\cos 10^\circ }}{2} - \frac{{\sqrt 3 }}{2}\sin 10^\circ } \right)}}{{(2\sin 10^\circ \cos 10^\circ ) \times \frac{1}{2}}}$

$ = \frac{{4\,\sin \,({{30}^o} - {{10}^o})}}{{\sin \,{{20}^o}}} $

$= \frac{{4\,\sin \,{{20}^o}}}{{\sin \,{{20}^o}}} = 4$.

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