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Trigonometry – II — Maths STD 11 Science — Question

Maharashtra BoardEnglish MediumSTD 11 ScienceMathsTrigonometry – II2 Marks
MCQ
$\frac{1}{\tan 3 A-\tan A}-\frac{1}{\cot 3 A-\cot A}=$
  • A
    tan A
  • B
    tan 2A
  • C
    cot A
  • ✓
    cot 2A
✓

Answer

Correct option: D.
cot 2A
(D)
$\frac{1}{\tan 3 A-\tan A}-\frac{1}{\cot 3 A-\cot A}$
$=\frac{1}{\tan 3 A-\tan A}+\frac{\tan A \tan 3 A}{\tan 3 A-\tan A}$
$=\frac{1}{\frac{\tan 3 A-\tan A }{1+\tan 3 A \cdot \tan A }}=\frac{1}{\tan 2 A}=\cot 2 A$

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