1 3A - A - 1 3A - A = - Vidyadip

MCQ

$\frac{1}{{\tan 3A - \tan A}} - \frac{1}{{\cot 3A - \cot A}} = $

A
$\tan A$
B
$\tan 2A$
C
$\cot A$
✓
$\cot 2A$

✓

Answer

Correct option: D.

$\cot 2A$

d
(d) $\frac{1}{{\tan 3A - \tan A}} - \frac{1}{{\cot 3A - \cot A}}$

$=\frac{1}{{\tan 3A - \tan A}} + \frac{{\tan A\tan 3A}}{{\tan 3A - \tan A}}$

$= \frac{1}{{\tan 2A}} = \cot 2A$.

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