Question
$\frac{-3^{100}}{5}=\frac{-3^{100}}{-5^{100}}$

Answer

True.
Solution:
$\Big(\frac{-3}{5}\Big)=\Big(\frac{-1\times3}{5}\Big)^{100}$ $\big[\because-3=1\times3\big]$
$\frac{(-1)^{100}\times3^{100}}{5^{100}}$ $\big[\because(\text{a}\times\text{b}^{\text{m}})=\text{a}^{\text{m}}\times\text{b}^{\text{m}}\big]$
$\frac{1\times3^{100}}{5^{100}}$ $\big[\because(-1)^{\text{n}}=1,\text{ if }\text{n}\text{ is even}\big]$
$\frac{3^{100}}{5^{100}}$
Now, taking RHS, we have $\frac{-3^{100}}{-5^{100}}=\frac{3^{10}}{5^{100}}$ [$\because$ if both numerator and denominator have negative sign, then it is cacelled out]
$\therefore$ LHS = RHS
Hence, $\frac{-3^{100}}{-5^{100}}=\frac{3^{10}}{5^{100}}$

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