MCQ
$\frac{-3}{5}-\left(\frac{-2}{15}\right)$ is equal to
- A$\frac{-11}{5}$
- B$\frac{-1}{15}$
- C$\frac{-7}{15}$
- D$\frac{7}{15}$
✓
Answer
$\begin{array}{c}
\frac{-3}{5}-\left(\frac{-2}{15}\right)=\frac{-3}{5}+\frac{2}{15} \\
=\frac{-9+2}{15}=\frac{-7}{15}\ \text{(c)}
\end{array}$
\frac{-3}{5}-\left(\frac{-2}{15}\right)=\frac{-3}{5}+\frac{2}{15} \\
=\frac{-9+2}{15}=\frac{-7}{15}\ \text{(c)}
\end{array}$
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