MCQ
$\frac{8^{1 / 3} \times 16^{1 / 3}}{32^{-1 / 3}}$ is equal to
- A2
- B4
- ✓16
- D8
✓
Answer
Correct option: C.
16
(c)
$\frac{8^{1 / 3} \times 16^{1 / 3}}{32^{-1 / 3}}=\frac{\left(2^3\right)^{1 / 3} \times\left(2^4\right)^{1 / 3}}{\left(2^5\right)^{-1 / 3}}=\frac{2^{3 \times \frac{1}{3}+4 \times \frac{1}{3}}}{2^{5 \times-\frac{1}{3}}}=\frac{2^{1+\frac{4}{3}}}{2^{-\frac{5}{3}}}=2^{1+\frac{4}{3}+\frac{5}{3}}=2^4=16$
$\frac{8^{1 / 3} \times 16^{1 / 3}}{32^{-1 / 3}}=\frac{\left(2^3\right)^{1 / 3} \times\left(2^4\right)^{1 / 3}}{\left(2^5\right)^{-1 / 3}}=\frac{2^{3 \times \frac{1}{3}+4 \times \frac{1}{3}}}{2^{5 \times-\frac{1}{3}}}=\frac{2^{1+\frac{4}{3}}}{2^{-\frac{5}{3}}}=2^{1+\frac{4}{3}+\frac{5}{3}}=2^4=16$
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