9 (4^x )^2 16^ x+1 -2^ x+1 8^x = - Vidyadip

MCQ

\[\frac{9\left(4^x\right)^2}{16^{x+1}-2^{x+1} \cdot 8^x}=\]

A
0
B
1
C
$\frac{14}{9}$
✓
$\frac{9}{14}$

✓

Answer

Correct option: D.

$\frac{9}{14}$

D

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