MCQ
$\frac{{{C_1}}}{{{C_0}}} + 2\frac{{{C_2}}}{{{C_1}}} + 3\frac{{{C_3}}}{{{C_2}}} + .... + 15\frac{{{C_{15}}}}{{{C_{14}}}} = $
- A$100$
- ✓$120$
- C$- 120$
- DNone of these
$\frac{{{C_1}}}{{{C_0}}} + 2\frac{{{C_2}}}{{{C_1}}} + 3\frac{{{C_3}}}{{{C_2}}} + .... + n.\frac{{{C_n}}}{{{C_{n - 1}}}} = \frac{{n(n + 1)}}{2}$
Putting $n=15$, then $\frac{{15 \times (15 + 1)}}{2} = 120$.
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