10 ^o + 10 ^o 10 ^o - 10 ^o = - Vidyadip

MCQ

$\frac{{\cos {{10}^o} + \sin {{10}^o}}}{{\cos {{10}^o} - \sin {{10}^o}}} = $

✓
$\tan \,{55^o}$
B
$\cot {55^o}$
C
$ - \tan {35^o}$
D
$ - \cot {35^o}$

✓

Answer

Correct option: A.

$\tan \,{55^o}$

a
(a) $\frac{{\cos {{10}^o} + \sin {{10}^o}}}{{\cos {{10}^o} - \sin {{10}^o}}}$

$ = \tan ({45^o} + {10^o}) = \tan {55^o}$.

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