MCQ
$\frac{{\cos 17^\circ + \sin 17^\circ }}{{\cos 17^\circ - \sin 17^\circ }} = $
- ✓$\tan 62^\circ $
- B$\tan 56^\circ $
- C$\tan 54^\circ $
- D$\tan 73^\circ $
we get, $\frac{{\cos \,\,{{17}^o} + \sin \,\,{{17}^o}}}{{\cos \,\,{{17}^o} - \sin \,\,{{17}^o}}}$
$ = \frac{{1 + \tan \,\,{{17}^o}}}{{1 - \tan \,\,{{17}^o}}} $
$= \frac{{\tan \,\,{{45}^o} + \tan \,\,{{17}^o}}}{{1 - \tan \,\,{{45}^o}\tan \,\,{{17}^o}}} = \tan \,\,{62^o}$.
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