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Trigonometry – II — Maths STD 11 Science — Question

Maharashtra BoardEnglish MediumSTD 11 ScienceMathsTrigonometry – II2 Marks
MCQ
$\frac{\cos 8^{\circ}-\sin 8^{\circ}}{\cos 8^{\circ}+\sin 8^{\circ}}$ is equal to
  • A
    $\tan 53^{\circ}$
  • ✓
    $\tan 37^{\circ}$
  • C
    $\tan 82^{\circ}$
  • D
    $\tan 62^{\circ}$
✓

Answer

Correct option: B.
$\tan 37^{\circ}$
(B)
$\frac{\cos 8^{\circ}-\sin 8^{\circ}}{\cos 8^{\circ}+\sin 8^{\circ}}=\frac{1-\tan 8^{\circ}}{1+\tan 8^{\circ}}$
$=\tan \left(45^{\circ}-8^{\circ}\right)=\tan 37^{\circ}$

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