MCQ
$\frac{\cos 9^{\circ}+\sin 9^{\circ}}{\cos 9^{\circ}-\sin 9^{\circ}}=$
  • $\tan 54^{\circ}$
  • B
    $\tan 36^{\circ}$
  • C
    $\tan 18^{\circ}$
  • D
    $\tan 9^{\circ}$

Answer

Correct option: A.
$\tan 54^{\circ}$
(A)
$\frac{\cos 9^{\circ}+\sin 9^{\circ}}{\cos 9^{\circ}-\sin 9^{\circ}}=\frac{1+\tan 9^{\circ}}{1-\tan 9^{\circ}}$
$=\tan \left(45^{\circ}+9^{\circ}\right)$ $\ldots\left[\because \tan 45^{\circ}=1\right]$
$=\tan 54^{\circ}$

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