Question
$\frac{d}{{dx}}\{ {(\sin x)^{\log x}}\} = $
$\Rightarrow {\log _e}y = {\log _e}x{\log _e}\sin x$
==> $\frac{{dy}}{{dx}} = {(\sin x)^{{{\log }_e}x}} = \left[ {\frac{1}{x}{{\log }_e}\sin x + \cot x{{\log }_e}x} \right]$.
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