MCQ
$\frac{\sin \theta}{1-\cot \theta}+\frac{\cos \theta}{1-\tan \theta}$ is equal to
- A$0$
- B1
- ✓$\sin \theta+\cos \theta$
- D$\sin \theta-\cos \theta$
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Assertion $(A)$
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Reason $(R)$
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The curved surface area of a cone of base radius $3 cm$ and height $4 cm$ is $15\pi\text{cm}^2$
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Volume of a cone $\pi\text{r}^2\text{h}$
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