Question
Divide: $12x^3y - 8x^2y^2 + 4x^2y^3 by 4xy$
✓
Answer
$12 x^3 y-8 x^2 y^2+4 x^2 y^3 \text { by } 4 x y $
$=\frac{12 x^3 y-8 x^2 y^2+4 x^2 y^3}{4 x y} $
$=\frac{12 x^3 y}{4 x y}-\frac{8 x^2 y^2}{4 x y}+\frac{4 x^2 y^3}{4 x y} $
$=3 x^2-2 x y+x y^2$
$=\frac{12 x^3 y-8 x^2 y^2+4 x^2 y^3}{4 x y} $
$=\frac{12 x^3 y}{4 x y}-\frac{8 x^2 y^2}{4 x y}+\frac{4 x^2 y^3}{4 x y} $
$=3 x^2-2 x y+x y^2$
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