Question
Divide $-4 a^3+4 a^2+a$ by $2 a$.

Answer

$\frac{-4\text{a}^3+4\text{a}^2+\text{a}}{2\text{a}}$
$=\frac{-4\text{a}^3}{2\text{a}}+\frac{4\text{a}^2}{2\text{a}}+\frac{\text{a}}{2\text{a}}$
$=-2\text{a}^{(3-1)}+2\text{a}^{(2-1)}+\frac{1}{2}$
$=-\text{2}\text{a}^2+2\text{a}+\frac{1}{2}$

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