Question
Divide $6 x^3 y^2 z^2$ by $3 x^2 y z$.
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Answer
$\frac{6\text{x}^3\text{y}^2\text{z}^2}{3\text{x}^2\text{yz}}=\frac{6\times\text{x}\times\text{x}\times\text{x}\times\text{y}\times\text{y}\times\text{z}\times\text{z}}{3\times\text{x}\times\text{x}\times\text{y}\times\text{z}}$
$=2\text{x}^{(3-2)}\text{y}^{(2-1)}\text{z}^{(2-1)}=2\text{xyz}$
$=2\text{x}^{(3-2)}\text{y}^{(2-1)}\text{z}^{(2-1)}=2\text{xyz}$
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