Divide 72 a^4 b^5 c^8 by -9 a^2 b^2 c^3. - Vidyadip

Question

Divide $72 a^4 b^5 c^8$ by $-9 a^2 b^2 c^3$.

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Answer

$\frac{72\text{a}^4\text{b}^5\text{c}^8}{-9\text{a}^2\text{b}^2\text{c}^3}$
$=\frac{72\times\text{a}\times\text{a}\times\text{a}\times\text{a}\times\text{b}\times\text{b}\times\text{b}\times\text{b}\times\text{b}\times\text{c}\times\text{c}\times\text{c}\times\text{c}\times\text{c}\times\text{c}\times\text{c}\times\text{c}}{-9\times\text{a}\times\text{a}\times\text{b}\times\text{b}\times\text{c}\times\text{c}\times\text{c}}$
$=8\text{a}^{(4-2)}\text{b}^{(5-2)}\text{c}^{(8-3)}$
$=8\text{a}^2\text{b}^3\text{c}^5$

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